Hi I have this working opening in a new instance using startapp. I am wanting to modify it to open the already open instance of excel. This is a snip from my lisp file.
(startapp "C:\\Program Files (x86)\\Microsoft Office\\Office14\\excel.exe " path))
path value is "\"Drive:\\Folder\\Subfolder\\99999*.xls"
path value is made from cutting parts out of the location of my current .dwg to find the related excel file. The excel file name is the same value as the folder my .dwg is plus a persons initials.
the excel filename can have additional charcters and will open correctly. I used .xls as it will open .xls and .xlsx just fine.
Hopefully this makes sense.
Rather than using "startapp" to start the excel program then opening the excel file iI just want the excel file to open in the excel that is already open. I just do not know what to use.