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Thread: How to count number of days

  1. 2013-02-01, 03:14 AM #1
    BeKirra
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    Default How to count number of days

    I tried to calculate the number of days to Christmas without success.

    Your helps are much appreciated.
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  2. 2013-02-01, 12:21 PM #2
    Tom Beauford
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    Default Re: How to count number of days

    Load julian.lsp from Express Tools. Use DTOJ to Converts AutoCAD calendar dates and time to Julian dates, subtract to get the difference.
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  3. 2013-02-04, 12:10 AM #3
    BeKirra
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    Default Re: How to count number of days

    Thanks Tom.
    This is what I have. Am I right?
    Code:
    (defun c:Test ()
(c:date)
(setq ChristmasIsComing (- (dtoj 20131225) (dtoj 20130205)))
(prompt (strcat "WOW! Christmas is coming in "
(rtos ChristmasIsComing 2 0)
" days!")
)
)
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  4. 2013-02-04, 07:35 AM #4
    pbejse
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    Default Re: How to count number of days

    Quote Originally Posted by BeKirra View Post
    Thanks Tom.
    This is what I have. Am I right?
    Code:
    (setq ChristmasIsComing (- (dtoj 20131225) (dtoj 20130205)))
    Code:
    (setq ChristmasIsComing (- (dtoj 20131225)
			   (dtoj (fix (getvar 'cdate)))))
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  5. 2013-02-04, 12:23 PM #5
    Tom Beauford
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    Default Re: How to count number of days

    Not sure what you're looking for, but here's a java ChristmasCountdown.htm file you can save to your computer and open with a browser just for fun.
    HTML Code:
    <html>
<head>
<TITLE>Christmas Countdown</TITLE>

<script language="javascript">
<!--
var count = new Date("December 25, 2013 07:00");
var timeUp = "Time to open presents!"

var timerID;
var timerRunning = false;
var today = new Date();
var persec = 0;
var permin = 0;
var perhour = 0;
var perday = 0;
var peryear = 0;
var secsRemain = 0;
var yearRemain = 0;
var dayRemain = 0;
var minRemain = 0;
var timeRemain = 0;
var expire = 0;

function stopclock (){
if(timerRunning)
clearTimeout(timerID);
timerRunning = false;
}

function startclock () {
stopclock();
showtime();
}

function showtime () {
today = new Date();
/*count.setYear(today.getYear());*/
persec = 1000;
permin = 60*persec;
perhour = 60*permin;
perday = 24*perhour;
peryear = 365*perday;

expire = (count.getTime() - today.getTime())

/*Seconds*/
secsRemain = (Math.floor(expire/persec))%60;
/*Minutes*/
minRemain = (Math.floor(expire/permin))%60;
/*Hours*/
hoursRemain = (Math.floor(expire/perhour))%24;
/*Days*/
daysRemain = Math.floor(expire/perday)%365;
/*Years*/
yearRemain = Math.floor(expire/peryear);

/*Handle single digits*/
if (hoursRemain < 10) hoursRemain = "0" + hoursRemain;
if (minRemain < 10) minRemain = "0" + minRemain;
if (secsRemain < 10) secsRemain = "0" + secsRemain;

/*Time*/

timeRemain ='';
timeRemain = yearRemain + ":" + daysRemain + ":" + hoursRemain + ":" + minRemain + ":" + secsRemain;

//if (yearRemain) { timeRemain += yearRemain; }
//if (daysRemain) { timeRemain += daysRemain; }
//if (hoursRemain) { timeRemain += hoursRemain; }
//if (minRemain) { timeRemain += minRemain; }
//if (secsRemain) { timeRemain += secsRemain; }
//timeRemain = yearRemain + daysRemain + hoursRemain + minRemain + secsRemain;
//timeRemain = daysRemain + hoursRemain + minRemain + secsRemain;
//timeRemain = hoursRemain + minRemain + secsRemain;

document.clock.face.value = timeRemain;
timerID = setTimeout("showtime()",1*persec);
timerRunning = true;

if (expire <= 0){
document.clock.face.value = timeUp;  // choose either "time" or "timeUp"  (without quotes)
stopclock();
}

}
// -->
</script>
</head>



<!-- <body bgcolor="#FFFFFF" text="#000000" link="#b09040" vlink="#806010" alink="#FF0000"> -->
<body bgcolor=green text=orange link="#b09040" vlink="#806010" alink="#FF0000">

</tr>
<tr><td colspan=3 valign=top width=449>


<!-- Start the Underhandle -->

<center>

<p>
&nbsp;

</p>


<!-- <p><strong><b><font size="2">NEXT UP...</font><br> -->
<font size="5"><i>Christmas Morning!</i></font><font face="Arial" size="3"><br><i>
December 25, 2013 07:00am</i></font></b>
<!-- </strong></p> -->
<form NAME="clock">
<p><b><font face="Arial" size="4">Better be good until<br>
</font></b><strong><font face="Arial" size="2">
Years:Days:Hours:Minutes:Seconds</font><br>
<font size="4">
<!-- <input TYPE="text" SIZE="12" NAME="face" style="font-size: 14pt; background-color: #800000; color: #FFFF00"></font><br> -->
<input TYPE="text" SIZE="11" NAME="face" style="font-size: 14pt; background-color: green; color: orange"></font><br>
<script LANGUAGE="JavaScript">
<!--
startclock()
// --> </script></p>
</form>

<p>
&nbsp;
</p>

</b></center>
</p>

</td></table>
<!-- End the Underhandle -->

<!-- All the stuff below the handle goes here -->

</BODY>
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  6. 2013-02-04, 10:09 PM #6
    BeKirra
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    Default Re: How to count number of days

    Thanks to Tom again.
    Your code is really fun! At this point I think it may be good to write a code for event reminder.
    And thanks to pbejse.

    BTW, I know there is different way to get the calendar day.
    Which one is better for my case and why? for example:
    Code:
    (menucmd "M=$(edtime,$(getvar,date),YYYYMODD)")
    and
    Code:
    (getvar 'cdate)
    Thanks again.
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  7. 2013-02-05, 04:55 AM #7
    pbejse
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    Default Re: How to count number of days

    Quote Originally Posted by BeKirra View Post
    BTW, I know there is different way to get the calendar day.
    Which one is better for my case and why? for example:

    Thanks again.
    (menucmd "m=$(edtime,$(getvar,date),yyyymodd)"):<-- The result is a string value

    To use the result for your purpose , you need to convert the string to a valid value for arithmetic function, in this case (-) subtraction
    (atoi (menucmd "m=$(edtime,$(getvar,date),yyyymodd)"))) --- > 20130204

    (getvar 'cdate) <---- result is Real number--> 2.01302e+007
    (fix (getvar 'cdate)) <---- result is integer --> 20130204

    HTH
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  8. 2013-02-05, 01:24 PM #8
    Tom Beauford
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    Default Re: How to count number of days

    Hadn't thought about diesel.
    Code:
     (menucmd "M=$(-,20131225,$(edtime,$(getvar,date),YYYYMODD))")
    gives you # of days till Christmas.
    Good reference for diesel is http://www.crlf.de/Dokumente/Diesel/Diesel.html
    I use it extensively in CUI's.
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  9. 2013-02-05, 10:07 PM #9
    BeKirra
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    Default Re: How to count number of days

    Thanks again.
    Now I agree with using "fix". It is really good for getting calendar date in the lisp code.

    And to Tom, I am afraid that I have to use "dtoj" from (c:date) because the following won't return an actual number of days but "1019" days:
    Code:
    (menucmd "M=$(-,20131225,$(edtime,$(getvar,date),YYYYMODD))")
    Hope my understanding is correct.
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  10. 2013-02-06, 12:59 PM #10
    Tom Beauford
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    Default Re: How to count number of days

    Quote Originally Posted by BeKirra View Post
    Thanks again.
    Now I agree with using "fix". It is really good for getting calendar date in the lisp code.

    And to Tom, I am afraid that I have to use "dtoj" from (c:date) because the following won't return an actual number of days but "1019" days:
    Code:
    (menucmd "M=$(-,20131225,$(edtime,$(getvar,date),YYYYMODD))")
    Hope my understanding is correct.
    Guess I should have error checked that.
    Code:
    (menucmd "M=$(-,2456652,$(fix,$(getvar,date)))")
    returns "322"
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