Set X until next setting of X

[mbrandt5]

(Setq X (getstring "\nEnter X Value: "))

The Value entered changes X...

How can I change the value of X to 1 within the lisp without requiring a string input such as (Setq X (1)), until the code runs across x again?

Having it change for every occurrence of Set X

So If I had...

(Setq X (1))

X would equal 1 until it gets to this part of the code

(Setq X (2))

X would equal 2 until it gets to this part of the code

(Setq X (3))

X would equal 3 until it gets to this part of the code

(Setq X (4))

[mbrandt5]

Nvm I realized it took a simple (set x 1)

[peter]

I think you may be a little confused so I will try to elaborate on Set and Setq.

(setq X (getstring "\nEnter String: "))

(set (quote X) (getstring "\nEnter String: "))

Are fundamentally equal.

You setting the symbol X to be a value.

setq and set are different functions

In your code above you have

 (setq X (1))

Should be

(setq X "1")

Since in you example you set X to a string.

If you want it to be a number

(setq X (getdist "\nEnter Number: "))

or

(setq X (getreal "\nEnter Number: "))

for whole numbers

(setq X (getint "\nEnter Integer: "))

for Integers

If I were you I would use setq and not use set.