Placing a point a known distance along a line segment

[jaycuda]

I have several hundred of these occurrences where I have a line segment that starts at Pt.A (0,0) and ends at a known Pt.B (X,Y). (See illustration)

Also known is the distance or length, L, along the line from the origin 0,0. I am trying to plot a point, Pt.C, at this location. I have tried doing the math in Excel but couldn't quite figure it out.

I am wondering if there is a way to programmatically plot this point using either a .scr or LISP routine, or even draw a line that ends at the point.
Any advice is appreciated!
9B15A4CF-2017-46E2-8B93-306377BB8E06.jpeg

[Tharwat]

Hi,
Initial example.

(entmake (list '(0 . "POINT") (cons 10 (polar pt_A (angle pt_A pt_B) len))))

[Ed Jobe]

The steps to do this would be to draw a point at L distance from point A, using the angle of line AB assuming the start point of AB is A. Another method would be to draw a temporary circle at point A with the radius of L and find the intersection of the circle and line AB. The latter would work for all quadrants.

[madcadder]

What you are looking for is the "measure" command, but it will place a point at every "L" distance from the beginning of line to the end, so you could end up with 12 points and having to erase 11.
Or you could just draw a circle from 0,0 with a radius of the "L" if you have multiple lines extending out from 0,0.

[BIG-AL]

Some more solutions to request https://www.cadtutor.net/forum/topic...-line-segment/